思路：先对 nums2 用单调栈求每个元素的下一个更大值，存入 Map 缓存；再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。
For lazy languages: determine which arguments are always evaluated，更多细节参见heLLoword翻译官方下载
10 monthly gift articles to share，推荐阅读safew官方版本下载获取更多信息
The cost of migrating a whole team to a custom thing can be expensive and time consuming. I'm definitely talking about this from the perspective of smaller / solo teams. But that said, speaking from experience, I know several middle-sized studios moving to custom engines because they have determined the potential risk of using proprietary engines to be too high, and the migration and learning costs to be worth it. I think using custom stuff for larger teams is easier now than it has been in a long time.。关于这个话题，同城约会提供了深入分析